Entropy AdvancedHardQuestion 31088
Question
A hot (90°C) and cold (10°C) body exchange heat reversibly via Carnot engine until they reach equilibrium temperature T_eq. T_eq is:
- A50°C
- B√(363×283) K − 273°CCorrect
- C(90+10)/2°C
- D10°C
Correct answer
√(363×283) K − 273°C
Explanation
For equal heat capacities, entropy is maximised (and Carnot work is maximised) at T_eq = √(T₁T₂) = √(363×283) ≈ 320 K = 47°C.