JEE Physics · Hard

Kinetic Theory and Thermodynamics: Entropy Advanced MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Entropy AdvancedHardQuestion 31088

Question

A hot (90°C) and cold (10°C) body exchange heat reversibly via Carnot engine until they reach equilibrium temperature T_eq. T_eq is:
  1. A
    50°C
  2. B
    √(363×283) K − 273°C
    Correct
  3. C
    (90+10)/2°C
  4. D
    10°C

Correct answer

√(363×283) K − 273°C

Explanation

For equal heat capacities, entropy is maximised (and Carnot work is maximised) at T_eq = √(T₁T₂) = √(363×283) ≈ 320 K = 47°C.