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Question 30239
JEE Physics · Medium

Laws of Motion and Friction: Impulse Momentum MCQ

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Impulse MomentumMediumQuestion 30239

Question

A force of 200 N acts on a 10 kg body for 0.05 s. Change in velocity is:
  1. A
    1 m/s
    Correct
  2. B
    0.1 m/s
  3. C
    10 m/s
  4. D
    100 m/s

Correct answer

1 m/s

Explanation

Impulse = FΔt = 200×0.05 = 10 N·s = Δp = mΔv. Δv = 10/10 = 1 m/s.

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