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Question 30265
JEE Physics · Medium

Laws of Motion and Friction: JEE — Friction Slope MCQ

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JEE — Friction SlopeMediumQuestion 30265

Question

The angle of friction φ is defined by tanφ = μ. For μₛ = 0.75, the angle of friction is approximately:
  1. A
    36.9°
    Correct
  2. B
    45°
  3. C
    26.6°
  4. D
    53.1°

Correct answer

36.9°

Explanation

tanφ = 0.75 → φ = arctan(0.75) ≈ 36.9°.

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