Momentum — RecoilMediumQuestion 30272
Question
A gun (3 kg) fires a bullet (0.01 kg) at 400 m/s. The recoil speed of the gun is:
- A1.33 m/sCorrect
- B4 m/s
- C133 m/s
- D0.01 m/s
Correct answer
1.33 m/s
Explanation
By conservation of momentum: 0 = 0.01×400 + 3×v_gun. v_gun = −4/3 = −1.33 m/s. Magnitude = 1.33 m/s.