Solenoid Field CalculationMediumQuestion 20204
Question
A solenoid has 2000 turns, length 0.5 m, and carries 3 A. The field inside is (μ₀ = 4π×10⁻⁷):
- A1.5×10⁻² T
- B2.4π×10⁻³ T
- C4.8π×10⁻³ TCorrect
- D1.2×10⁻² T
Correct answer
4.8π×10⁻³ T
Explanation
n = 2000/0.5 = 4000 turns/m. B = μ₀nI = 4π×10⁻⁷ × 4000 × 3 = 4.8π×10⁻³ T ≈ 1.508×10⁻² T.