JEE Physics · Hard

Principles of Communication: Digital Communication MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Digital CommunicationHardQuestion 20269

Question

A channel has bandwidth 3 kHz and SNR = 63. By Shannon's formula, the maximum channel capacity is:
  1. A
    18 kbps
    Correct
  2. B
    9 kbps
  3. C
    63 kbps
  4. D
    6 kbps

Correct answer

18 kbps

Explanation

C = B log₂(1 + S/N) = 3000 × log₂(64) = 3000 × 6 = 18,000 bps = 18 kbps. Note log₂(64) = 6 since 2⁶ = 64. Telephone voice channels achieve close to this with modern codecs.