Digital CommunicationHardQuestion 20269
Question
A channel has bandwidth 3 kHz and SNR = 63. By Shannon's formula, the maximum channel capacity is:
- A18 kbpsCorrect
- B9 kbps
- C63 kbps
- D6 kbps
Correct answer
18 kbps
Explanation
C = B log₂(1 + S/N) = 3000 × log₂(64) = 3000 × 6 = 18,000 bps = 18 kbps. Note log₂(64) = 6 since 2⁶ = 64. Telephone voice channels achieve close to this with modern codecs.