JEE Physics · Hard

Principles of Communication: Digital Communication MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Digital CommunicationHardQuestion 20301

Question

The Nyquist formula for noiseless channel capacity is C = 2B log₂(M) where M is the number of signal levels. A noiseless channel of 3 kHz bandwidth using 16 signal levels has capacity:
  1. A
    6 kbps
  2. B
    12 kbps
  3. C
    24 kbps
    Correct
  4. D
    48 kbps

Correct answer

24 kbps

Explanation

C = 2 × 3000 × log₂(16) = 6000 × 4 = 24,000 bps = 24 kbps. This is the Nyquist (noiseless) limit. In practice, Shannon's theorem (which includes SNR) further limits capacity. For 3 kHz with SNR = 255: C = 3000 × log₂(256) = 24 kbps — same numerically by coincidence here.