Compound Microscope — MagnificationMediumQuestion 20232
Question
Magnifying power of a compound microscope (objective f_o, eyepiece f_e, tube length L) for image at infinity is approximately:
- A(L/f_o)(D/f_e)Correct
- B(L+f_o)(D/f_e)
- C(D/f_o)(L/f_e)
- D(f_o/L)(D/f_e)
Correct answer
(L/f_o)(D/f_e)
Explanation
M = m_o × M_e ≈ (L/f_o) × (D/f_e) for image at infinity. Short f_o and f_e → high magnification. The objective forms a real magnified image; the eyepiece acts as a simple microscope magnifying that image.