Prism — Minimum DeviationHardQuestion 20241
Question
A prism of apex angle 60° has n = √3. Minimum deviation angle is:
- A30°
- B60°Correct
- C45°
- D90°
Correct answer
60°
Explanation
n = sin[(A+D_m)/2]/sin(A/2) = sin[(60+D_m)/2]/sin30°. √3 = sin[(60+D_m)/2]/0.5 → sin[(60+D_m)/2] = √3/2 = sin60° → (60+D_m)/2 = 60° → D_m = 60°.