Lens — Diverging Lens AlwaysEasyQuestion 20254
Question
A concave (diverging) lens always forms an image that is:
- AReal, inverted, diminished
- BVirtual, erect, diminishedCorrect
- CVirtual, erect, magnified
- DReal, erect, same size
Correct answer
Virtual, erect, diminished
Explanation
For a diverging lens with any real object position: image is always virtual, erect, and smaller. m = v/u where v < |u| → |m| < 1 (diminished). The image appears on the same side as the object.