JEE Physics · Hard

Rigid Body Dynamics: Rolling — Energy Split MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Rolling — Energy SplitHardQuestion 30348

Question

A hollow cylinder (I = MR²) rolls down from height h on an incline. At the bottom, the fraction of total KE that is translational is:
  1. A
    1/2
    Correct
  2. B
    2/3
  3. C
    5/7
  4. D
    3/5

Correct answer

1/2

Explanation

For hollow cylinder: KE_trans = ½mv², KE_rot = ½Iω² = ½MR²(v/R)² = ½mv². Total = mv². Translational fraction = (½mv²)/mv² = 1/2.