Torque — Compound PendulumHardQuestion 30350
Question
A rod (mass M, length L) pivoted at one end swings as a pendulum. The restoring torque when displaced by small angle θ is:
- AMgL sinθ ≈ MgLθ
- BMg(L/2)sinθ ≈ Mg(L/2)θCorrect
- CMgLθ/2
- DMgL cosθ
Correct answer
Mg(L/2)sinθ ≈ Mg(L/2)θ
Explanation
Gravity acts at the centre of mass (L/2 from pivot). Restoring torque = Mg(L/2)sinθ ≈ Mg(L/2)θ for small θ.