JEE — MOI ApplicationMediumQuestion 30357
Question
The radius of gyration of a solid sphere (radius R) about its diameter is:
- AR
- BR/√5
- CR√(2/5)Correct
- DR/2
Correct answer
R√(2/5)
Explanation
I = (2/5)MR² = Mk² → k² = (2/5)R² → k = R√(2/5).
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
I = (2/5)MR² = Mk² → k² = (2/5)R² → k = R√(2/5).