JEE — Rotation KinematicsMediumQuestion 30361
Question
A disc (I = 0.5 kg·m²) is accelerated from ω = 2 rad/s to ω = 10 rad/s by a constant torque in 4 s. The torque is:
- A1 N·mCorrect
- B2 N·m
- C4 N·m
- D0.5 N·m
Correct answer
1 N·m
Explanation
α = (10−2)/4 = 2 rad/s². τ = Iα = 0.5×2 = 1 N·m.