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Question 30370
JEE Physics · Hard

Rigid Body Dynamics: JEE — Combined Translation+Rotation MCQ

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JEE — Combined Translation+RotationHardQuestion 30370

Question

A 2 kg disc (R = 0.4 m, I = 0.16 kg·m²) rolling at v = 3 m/s. Total kinetic energy is:
  1. A
    9 J
  2. B
    13.5 J
    Correct
  3. C
    6 J
  4. D
    4.5 J

Correct answer

13.5 J

Explanation

KE = ½mv² + ½Iω² = ½×2×9 + ½×0.16×(3/0.4)² = 9 + ½×0.16×56.25 = 9 + 4.5 = 13.5 J.

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