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Question 30378
JEE Physics · Hard

Rigid Body Dynamics: Advanced — Energy in Rotation MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Advanced — Energy in RotationHardQuestion 30378

Question

A thin circular ring (mass M, radius R) is set rolling at speed v on a horizontal surface. It encounters a rough patch and comes to rest. Heat generated is:
  1. A
    ½Mv²
  2. B
    Mv²
    Correct
  3. C
    3Mv²/4
  4. D
    Mv²/4

Correct answer

Mv²

Explanation

For a ring (I = MR²): Total KE = ½Mv² + ½MR²(v/R)² = ½Mv² + ½Mv² = Mv². All KE is converted to heat when it stops.

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