EnergyMediumQuestion 31124
Question
At what displacement is KE = PE in SHM?
- Ax = A/2
- Bx = A/√2Correct
- Cx = A√2
- Dx = A/4
Correct answer
x = A/√2
Explanation
KE = PE: ½mω²(A²−x²) = ½mω²x² → A² − x² = x² → x = A/√2.
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
KE = PE: ½mω²(A²−x²) = ½mω²x² → A² − x² = x² → x = A/√2.