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Question 31129
JEE Physics · Medium

Simple Harmonic Motion: KE Variation MCQ

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KE VariationMediumQuestion 31129

Question

Average kinetic energy over a complete cycle of SHM is:
  1. A
    ½mω²A²
  2. B
    ¼mω²A²
    Correct
  3. C
    mω²A²
  4. D
    0

Correct answer

¼mω²A²

Explanation

KE = ½mω²(A²−x²). Average KE = ½ × total energy = ½ × ½mω²A² = ¼mω²A². Same for average PE.

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