Simple Harmonic Motion: Energy MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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EnergyHardQuestion 31138

Question

In SHM, PE = KE at t = 0 (particle starts from x = A/√2). Time to reach mean position first is:

A
T/8
Correct
B
T/4
C
T/6
D
T/12

Correct answer

T/8

Explanation

x = A/√2 corresponds to ωt = π/4. Starting from x = A/√2 (positive), mean position is at ωt = π/2... actually from x = A/√2: x = A sin(ωt+φ) at t=0, x=A/√2 → sin(φ)=1/√2 → φ = π/4. x = 0 when ωt + π/4 = π → t = 3π/(4ω) = 3T/8. First: ωt + π/4 = π gives t= 3T/8. The answer depends on direction.

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