Home/
Competitive Exams/
JEE Main & Advanced/
Physics/
Simple Harmonic Motion/
Question 31188
JEE Physics · Hard

Simple Harmonic Motion: SHM Advanced MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
SHM AdvancedHardQuestion 31188

Question

A block on a frictionless surface is connected to two walls by springs k₁ and k₂. Normal mode frequency is:
  1. A
    √((k₁+k₂)/m)/(2π)
    Correct
  2. B
    √(k₁k₂/(m(k₁+k₂)))/(2π)
  3. C
    √(k₁/(m))/(2π)
  4. D
    √(k₂/(m))/(2π)

Correct answer

√((k₁+k₂)/m)/(2π)

Explanation

Both springs restore simultaneously in parallel: k_eff = k₁ + k₂. f = (1/2π)√((k₁+k₂)/m).

Review Simple Harmonic Motion notesStart timed chapter practice