Sound Waves: Doppler Application MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Doppler ApplicationMediumQuestion 31267

Question

A bat emits 50,000 Hz and moves at 10 m/s toward a wall. Echo frequency heard by bat (v_sound = 330 m/s):

53125 Hz

Wall reflects as apparent source at f₁ = 50000×330/(330−10) = 51562 Hz. Then bat hears echo: f₂ = f₁×(330+10)/330 = 51562×340/330 ≈ 53125 Hz.