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JEE Physics · Hard

Waves on String: Wave Equation MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Wave EquationHardQuestion 31316

Question

Slope of string at any position x, t is ∂y/∂x = −Ak cos(ωt−kx). This represents:
  1. A
    Transverse velocity
  2. B
    Local angle of string from horizontal
    Correct
  3. C
    Wave speed
  4. D
    Frequency

Correct answer

Local angle of string from horizontal

Explanation

∂y/∂x is the slope at point x — the tangent angle. For small amplitudes, angle θ ≈ ∂y/∂x (in radians).

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