SonometerHardQuestion 31334
Question
Two sonometer wires of lengths L₁ and L₂ are in unison. Tension in wire 1 is halved. To maintain unison, L₁ must become:
- AL₁/√2Correct
- BL₁√2
- C2L₁
- DL₁/2
Correct answer
L₁/√2
Explanation
f ∝ √T/L. Wire 1: f = √T₁/L₁ = √(T₁/2)/L₁'. For same f: L₁' = L₁ × √(T₁/2)/√T₁ = L₁/√2.