JEE Physics · Hard

Waves on String: Harmonics MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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HarmonicsHardQuestion 31336

Question

String A (length L, μ) and String B (length 2L, 4μ) under same tension. Ratio of fundamental frequencies f_A:f_B is:
  1. A
    4:1
    Correct
  2. B
    1:4
  3. C
    2:1
  4. D
    1:2

Correct answer

4:1

Explanation

f_A = v_A/(2L) = √(T/μ)/(2L). f_B = v_B/(4L) = √(T/4μ)/(4L) = √(T/μ)/(8L). f_A/f_B = (1/(2L))/(1/(8L)) = 4. Ratio 4:1.