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Question 31338
JEE Physics · Hard

Waves on String: Standing Waves MCQ

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Standing WavesHardQuestion 31338

Question

In standing wave y = 2A sin(kx)cos(ωt), maximum energy is at antinodes and zero at nodes. Time-averaged KE and PE in one loop:
  1. A
    KE = PE always
  2. B
    KE = PE (time averaged over full cycle)
    Correct
  3. C
    KE = 0, PE = maximum
  4. D
    PE = 0 always

Correct answer

KE = PE (time averaged over full cycle)

Explanation

Time-averaged KE = time-averaged PE for a standing wave over a complete cycle. Instantaneously they differ (KE max when PE = 0 at cos²ωt = 1, and vice versa).

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