One End FixedHardQuestion 31351
Question
3rd harmonic of string fixed at one end, free at other of length 1 m (v = 200 m/s):
- A50 Hz
- B150 HzCorrect
- C100 Hz
- D200 Hz
Correct answer
150 Hz
Explanation
f_n = nv/(4L) for odd n. f₃ = 3×200/4 = 150 Hz.
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
f_n = nv/(4L) for odd n. f₃ = 3×200/4 = 150 Hz.