SonometerHardQuestion 31371
Question
Sonometer wire of length L vibrates in p-th harmonic at f₁. Wire length changed to L/q. Frequency now:
- Aqf₁/p
- Bpf₁/q
- Cq²f₁
- Dqf₁Correct
Correct answer
qf₁
Explanation
Original: f₁ = pv/(2L). New length L/q, fundamental of new length: f = v/(2×L/q) = qv/(2L). If comparing fundamental: f_new = qv/(2L) = q×(f₁/p)×... This depends on which harmonic is excited. If same harmonic p: f_new = pv/(2×L/q) = qpv/(2L) = qf₁.