Waves on String: Melde's Experiment MCQ

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Melde's ExperimentHardQuestion 31375

Question

In Melde's transverse mode, a 1.5 m string forms 3 loops at a tension of 0.09 N and a frequency of 50 Hz. Its mass per unit length is:

3.6×10⁻⁵ kg/m

Using $f=n\sqrt{T/μ}/(2L)$ gives $50=3\sqrt{0.09/μ}/3=\sqrt{0.09/μ}$ . Therefore $μ=0.09/50^2=<strong>3.6×10^{-5}\text{ kg/m}</strong>$ .