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Question 31383
JEE Physics · Hard

Waves on String: Normal Modes MCQ

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Normal ModesHardQuestion 31383

Question

String fixed at x=0 and x=L. For n=2 mode, nodes are at:
  1. A
    x = 0, L
  2. B
    x = 0, L/2, L
    Correct
  3. C
    x = L/4, 3L/4
  4. D
    x = 0, L/3, 2L/3, L

Correct answer

x = 0, L/2, L

Explanation

2nd harmonic (n=2): 3 nodes at x = 0, L/2, L. 2 antinodes at x = L/4, 3L/4.

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