Projectile EnergyMediumQuestion 30421
Question
A ball is thrown with KE = 40 J at 45°. At the highest point, its KE is:
- A0
- B20 JCorrect
- C40 J
- D28.3 J
Correct answer
20 J
Explanation
At the highest point, vertical velocity = 0. Horizontal component: v_x = v cos45° = v/√2. KE = ½m(v/√2)² = ½mv²/2 = 40/2 = 20 J.