JEE Physics · Medium

Work, Power and Energy: Projectile Energy MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Projectile EnergyMediumQuestion 30421

Question

A ball is thrown with KE = 40 J at 45°. At the highest point, its KE is:
  1. A
    0
  2. B
    20 J
    Correct
  3. C
    40 J
  4. D
    28.3 J

Correct answer

20 J

Explanation

At the highest point, vertical velocity = 0. Horizontal component: v_x = v cos45° = v/√2. KE = ½m(v/√2)² = ½mv²/2 = 40/2 = 20 J.