JEE Physics · Hard

Work, Power and Energy: Work-Energy — Incline with Friction MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Work-Energy — Incline with FrictionHardQuestion 30426

Question

A 2 kg block starts at rest and slides 5 m down a 30° rough incline (μₖ = 0.2). Speed at bottom: (g = 10, sin30° = 0.5, cos30° = 0.866)
  1. A
    5 m/s
  2. B
    4.12 m/s
    Correct
  3. C
    7 m/s
  4. D
    3 m/s

Correct answer

4.12 m/s

Explanation

W_net = W_gravity + W_friction = mg sinθ × L − μₖmg cosθ × L = 2×10×0.5×5 − 0.2×2×10×0.866×5 = 50 − 17.32 = 32.68 J. v = √(2×32.68/2) = √32.68 ≈ 5.72 m/s. (checking: mgL sinθ = 50, friction work = 0.2×2×10×0.866×5 = 17.32, net = 32.68, v = √(32.68) ≈ 5.72)