Escape Speed Using EnergyHardQuestion 30449
Question
The escape speed from the Moon's surface (radius Rm = 1.74×10⁶ m, g_moon = 1.63 m/s²) is approximately:
- A1680 m/s
- B2380 m/sCorrect
- C11200 m/s
- D840 m/s
Correct answer
2380 m/s
Explanation
v_escape = √(2g_moon×R_m) = √(2×1.63×1.74×10⁶) = √(5.67×10⁶) ≈ 2381 m/s ≈ 2.38 km/s.