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Question 30464
JEE Physics · Hard

Work, Power and Energy: JEE — Spring Vertical MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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JEE — Spring VerticalHardQuestion 30464

Question

A block (mass m) is dropped from rest onto a vertical spring (k). The spring compresses maximally by d. Using energy conservation:
  1. A
    kd = mg
  2. B
    ½kd² = mgd
  3. C
    ½kd² = mg(h+d) where h is drop height
    Correct
  4. D
    kd² = mgh

Correct answer

½kd² = mg(h+d) where h is drop height

Explanation

Block falls height h above spring, then spring compresses by d. Total PE decrease = mg(h+d). PE stored in spring = ½kd². Setting equal: ½kd² = mg(h+d).

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