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Question 24032
NEET Chemistry · Medium

Equilibrium: Ka MCQ

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KaMediumQuestion 24032

Question

Acid dissociation constant for HA is:

  1. A
    Ka=[H+][A−][HA]K_a=\dfrac{[H^+][A^-]}{[HA]}
    Correct
  2. B
    Ka=[HA][H+][A−]K_a=\dfrac{[HA]}{[H^+][A^-]}
  3. C
    Ka=[H+][HA]K_a=[H^+][HA]
  4. D
    Ka=[A−]/[H+]K_a=[A^-]/[H^+]

Correct answer

Ka=[H+][A−][HA]K_a=\dfrac{[H^+][A^-]}{[HA]}

Explanation

This expression measures acid strength.

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