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NEET Chemistry · Hard

Equilibrium: Buffer relation MCQ

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Buffer relationHardQuestion 24068

Question

For an acidic buffer, Henderson equation is:

  1. A
    pH=pKa+log⁡[salt][acid]pH=pK_a+\log\dfrac{[salt]}{[acid]}
    Correct
  2. B
    pH=pKa−log⁡[salt][acid]pH=pK_a-\log\dfrac{[salt]}{[acid]}
  3. C
    pH=pOH+14pH=pOH+14
  4. D
    pH=log⁡KapH=\log K_a

Correct answer

pH=pKa+log⁡[salt][acid]pH=pK_a+\log\dfrac{[salt]}{[acid]}

Explanation

This is the Henderson-Hasselbalch form.

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