Oxidation numberMediumQuestion 25005
Question
Oxidation number of sulfur in is:
- A+4Correct
- B+6
- C+2
- D0
Correct answer
+4
Explanation
Let sulfur be x: x + 2(-2) = 0, so x = +4.
Solve this quality-checked NEET multiple-choice question, then review the correct answer and explanation.
Oxidation number of sulfur in is:
Let sulfur be x: x + 2(-2) = 0, so x = +4.