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Question 6271
NEET Physics · Hard

Gravitation: Orbital Mechanics MCQ

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Orbital MechanicsHardQuestion 6271

Question

For a satellite in circular orbit, PE = −2KE. Total energy:
  1. A
    −KE
    Correct
  2. B
    KE
  3. C
    −KE/2
  4. D
    2KE

Correct answer

−KE

Explanation

TE = KE + PE = KE − 2KE = −KE. Total energy equals negative of KE.

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