Gravitation MixedHardQuestion 6288
Question
A satellite close to Earth surface (h ≈ 0). Period T₀ = 2π√(R/g). If g = 10 m/s², R = 6.4×10⁶ m, T₀:
- A~84 minCorrect
- B~24 h
- C~48 min
- D~12 h
Correct answer
~84 min
Explanation
T = 2π√(6.4×10⁶/10) = 2π×800 ≈ 5026 s ≈ 84 min.