Conservation of MomentumMediumQuestion 5423
Question
A gun (3 kg) fires a bullet (50 g) at 400 m/s. The recoil speed of the gun is:
- A2 m/s
- B4 m/s
- C20/3 m/sCorrect
- D6 m/s
Correct answer
20/3 m/s
Explanation
Conservation of momentum: 0 = 3V + 0.05×400. 3V = −20. V = 20/3 ≈ 20/3 m/s.