Mixed Laws of MotionMediumQuestion 5447
Question
A bullet (10 g) moving at 400 m/s is stopped in 0.01 s. The retarding force is:
- A400 NCorrect
- B4000 N
- C40 N
- D4 N
Correct answer
400 N
Explanation
F = m(Δv/Δt) = 0.01 × (400/0.01) = 0.01 × 40000 = 400 N.