Fluid PressureHardQuestion 6424
Question
Equivalent height of atmosphere at sea level pressure (avg density ρ_air=1.2 kg/m³, P₀=10⁵ Pa, g=10):
- A~8.33 kmCorrect
- B~100 km
- C~1 km
- D~76 m
Correct answer
~8.33 km
Explanation
h = P/(ρg) = 10⁵/(1.2×10) = 10⁵/12 ≈ 8333 m ≈ 8.33 km.