Stress and StrainHardQuestion 6315
Question
A 2 m wire (cross-section 2 mm²) stretched by 1 mm. Y = 2×10¹¹ Pa. Force applied:
- A200 NCorrect
- B2000 N
- C20 N
- D0.2 N
Correct answer
200 N
Explanation
F = YA ΔL/L = 2×10¹¹ × 2×10⁻⁶ × 10⁻³/2 = 2×10¹¹ × 10⁻⁹ = 200 N.