Hooke's LawEasyQuestion 6324
Question
A spring is stretched by 5 cm with force 10 N. Spring constant k:
- A2 N/m
- B50 N/m
- C200 N/mCorrect
- D0.02 N/m
Correct answer
200 N/m
Explanation
k = F/x = 10/(0.05) = 200 N/m.
Solve this quality-checked NEET multiple-choice question, then review the correct answer and explanation.
k = F/x = 10/(0.05) = 200 N/m.