NEET Physics · Hard

Mechanical Properties of Solids: Thermal Stress MCQ

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Thermal StressHardQuestion 6372

Question

A copper rod (Y=10¹¹ Pa, α=17×10⁻⁶/°C, A=1 cm²) heated by 100°C (fixed ends). Compressive force:
  1. A
    17 kN
    Correct
  2. B
    170 kN
  3. C
    1.7 kN
  4. D
    17 N

Correct answer

17 kN

Explanation

σ = YαΔT = 10¹¹×17×10⁻⁶×100 = 1.7×10⁸ Pa. F = σA = 1.7×10⁸×10⁻⁴ = 17,000 N = 17 kN.