Mixed Motion ConceptsHardQuestion 5249
Question
A body thrown vertically up passes a point P at height h with velocity v. The maximum height reached above P is:
- Av/2g
- Bv²/2gCorrect
- Cv²/g
- D2v²/g
Correct answer
v²/2g
Explanation
At P, velocity = v (upward). Extra height above P: using v² = 2gH → H = v²/2g.