Advanced Dimensional AnalysisHardQuestion 5042
Question
If E = hf where h is Planck's constant and f is frequency, the dimensions of h are:
- A[ML²T⁻¹]Correct
- B[MLT⁻¹]
- C[ML²T⁻²]
- D[ML³T⁻²]
Correct answer
[ML²T⁻¹]
Explanation
h = E/f. [E] = [ML²T⁻²], [f] = [T⁻¹]. So [h] = [ML²T⁻²]/[T⁻¹] = [ML²T⁻¹].