Conservation of EnergyMediumQuestion 6041
Question
At midpoint of freely falling body from height H, its KE equals:
- Amgh
- BmgH/2Correct
- C2mgH
- DmgH/4
Correct answer
mgH/2
Explanation
At h = H/2: KE = Total − PE = mgH − mgH/2 = mgH/2.
Solve this quality-checked NEET multiple-choice question, then review the correct answer and explanation.
At h = H/2: KE = Total − PE = mgH − mgH/2 = mgH/2.