Conservation of EnergyHardQuestion 6044
Question
Ball thrown at 30° with KE = 10 J. KE at maximum height:
- A10 J
- B7.5 JCorrect
- C2.5 J
- D5 J
Correct answer
7.5 J
Explanation
At max height, KE = KE₀cos²30° = 10×(3/4) = 7.5 J.
Solve this quality-checked NEET multiple-choice question, then review the correct answer and explanation.
At max height, KE = KE₀cos²30° = 10×(3/4) = 7.5 J.