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Practice Test 6
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SSC CGL Number System Verified Practice Test 6

15 structurally validated Number System questions with unique options, mapped answers and explanations.

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SSC CGL Practice Session

SSC CGL Number System Verified Practice Test 6

15 structurally validated Number System questions with unique options, mapped answers and explanations.

Questions
15
Marking
+2 correct, -0.5 wrong
Format
15-question practice session
Preview all 15 questions in SSC CGL Number System Verified Practice Test 6 (no login required)
  1. Factors

    1. How many factors does 72 have?

    • A. 9
    • B. 12 (Correct)
    • C. 15
    • D. 18

    Explanation: 72=2^3×3^2, factors=(3+1)(2+1)=12.

  2. LCM-HCF

    2. Product of two numbers is 1080 and their HCF is 6. Their LCM is:

    • A. 180 (Correct)
    • B. 200
    • C. 210
    • D. 220

    Explanation: LCM = Product/HCF = 1080/6 = 180.

  3. Divisibility

    3. The largest 4-digit number divisible by 18 is:

    • A. 9990 (Correct)
    • B. 9972
    • C. 9981
    • D. 9999

    Explanation: 9990 ÷ 18 = 555 exactly.

  4. Remainder

    4. Find the remainder when 99! is divided by 100.

    • A. 0 (Correct)
    • B. 1
    • C. 25
    • D. 50

    Explanation: Since 99! contains both 4 and 25 as factors, it is divisible by 100.

  5. Unit Digit

    5. Unit digit of 3^47 is:

    • A. 1
    • B. 3
    • C. 7 (Correct)
    • D. 9

    Explanation: Powers of 3 cycle as 3, 9, 7, 1. Since 47 leaves remainder 3 when divided by 4, the unit digit is 7.

  6. HCF

    6. Three bells ring at intervals of 6, 8, and 12 minutes. If they ring together at 8:00 AM, when will they ring together again?

    • A. 8:24 AM (Correct)
    • B. 8:30 AM
    • C. 8:36 AM
    • D. 8:48 AM

    Explanation: LCM(6,8,12)=24 minutes. They ring together at 8:24 AM.

  7. Number Property

    7. A number when divided by 5 gives remainder 3 and divided by 7 gives remainder 4. Which of these fits?

    • A. 18
    • B. 28
    • C. 53 (Correct)
    • D. 39

    Explanation: 53÷5=10 rem 3, 53÷7=7 rem 4. Both conditions satisfied.

  8. Factors

    8. Find the number of zeros at the end of 50!.

    • A. 10
    • B. 12 (Correct)
    • C. 13
    • D. 15

    Explanation: Zeros = ⌊50/5⌋+⌊50/25⌋ = 10+2 = 12.

  9. Divisibility

    9. Which is the smallest number divisible by both 8 and 12?

    • A. 16
    • B. 24 (Correct)
    • C. 36
    • D. 48

    Explanation: LCM(8,12) = 24.

  10. Divisibility

    10. A number is divisible by both 4 and 6. It must be divisible by:

    • A. 10
    • B. 12 (Correct)
    • C. 18
    • D. 24

    Explanation: LCM(4,6)=12. The number must be divisible by 12.

  11. Unit Digit

    11. Unit digit of 2^100 is:

    • A. 2
    • B. 4
    • C. 6 (Correct)
    • D. 8

    Explanation: Powers of 2 cycle: 2,4,8,6 (period 4). 100÷4=25 remainder 0. Unit digit = 6.

  12. Factors

    12. Number of prime factors of 2^3 × 3^2 × 5 is:

    • A. 3 (Correct)
    • B. 4
    • C. 5
    • D. 6

    Explanation: Number of distinct prime factors = 3 (i.e., 2, 3, and 5).

  13. Remainder

    13. Remainder when 17 × 19 × 21 is divided by 4:

    • A. 0
    • B. 1
    • C. 2
    • D. 3 (Correct)

    Explanation: 17≡1, 19≡3, 21≡1 (mod 4). Product≡1×3×1=3 (mod 4).

  14. HCF LCM

    14. HCF of two numbers is 8 and LCM is 384. One number is 48. Other is:

    • A. 56
    • B. 64 (Correct)
    • C. 72
    • D. 80

    Explanation: Other = HCF×LCM/one number = 8×384/48 = 64.

  15. Number Property

    15. Sum of all prime numbers between 1 and 20 is:

    • A. 55
    • B. 58
    • C. 60
    • D. 77 (Correct)

    Explanation: Primes: 2+3+5+7+11+13+17+19=77.