1. Audit the carbonate electron count
Find the valence-electron total in CO₃²⁻ and formal charges in a contributor with one C=O and two C–O bonds.
Total = 4 + 3 × 6 + 2 = 24 electrons. Carbon: 4 − 0 − 8/2 = 0. Double-bonded oxygen: 6 − 4 − 4/2 = 0. Each single-bonded oxygen: 6 − 6 − 2/2 = −1. Total = −2. Three equivalent contributors give mean C–O bond order 4/3 in the resonance model.
2. Separate electron arrangement from shape
What are the electron-domain arrangement and molecular shape of ClF₃?
There are 28 valence electrons. Three Cl–F bonds and the terminal F octets leave four electrons on Cl: two lone pairs. Five domains give a trigonal-bipyramidal arrangement. Two equatorial lone pairs leave a T-shaped molecule.
3. Check polarity despite lone pairs
Does XeF₄ have a permanent molecular dipole in its ideal equilibrium geometry?
Its 36 valence electrons leave two lone pairs on Xe after four bonds and the F octets. Six domains give an octahedral arrangement; opposite lone pairs leave square-planar XeF₄. The four equal Xe–F bond dipoles cancel, giving zero net permanent dipole.
4. Compare oxygen ions
Find bond orders and unpaired-electron counts for O₂⁺, O₂ and O₂⁻ using the standard MO filling.
The bonding valence-electron count is 8. Antibonding counts are 3, 4 and 5 respectively. Bond orders are 2.5, 2 and 1.5. The π* occupancies give 1, 2 and 1 unpaired electrons. All three are paramagnetic in this model; O₂⁺ is predicted to have the shortest bond of this set.
5. Count σ and π bonds
How many σ and π bonds are in H–C≡C–H?
The C≡C bond contributes one σ and two π bonds. The two C–H bonds each contribute one σ. Total: 3 σ and 2 π. Each carbon has two bonding directions and an sp description.
6. Diagnose an invalid angle calculation
A learner subtracts 2° for each of water's two lone pairs from 109.5° and reports 105.5°. Is that a justified prediction?
No. VSEPR gives a bent shape, not a fixed subtraction rule. Water's gas-phase angle is about 104.5°. Use a supplied or established angle when a numerical value is needed; molecular identity matters.